factorial-positive
0.1 Factorial
For any natural number \(n\), we define the factorial of \(n\), denoted by \(n!\), recursively as:
\(0! = 1\)
\((n+1)! = (n+1) \cdot n!\)
For every natural number \(n\), the factorial of \(n\) is strictly positive:
\[ n! {\gt} 0 \]
Proof
By induction on \(n\).
Base case: \(0! = 1 {\gt} 0\).
Inductive step: Assume \(n! {\gt} 0\). Then \((n+1)! = (n+1) \cdot n!\). Since \(n+1 {\gt} 0\) and \(n! {\gt} 0\) (by inductive hypothesis), their product is positive.